A foul tip of a baseball is hit straight upward from a height of 4 feet with an initial velocity of 64 feet per second

A foul tip of a baseball is hit straight upward from a height of 4 feet with an initial velocity of 64 feet per second. The function s(t) = -16t 2 + 64t + 4 describes the ball’s height above the ground, s(t), in feet, t seconds after it is hit. Solve, a. What is the instantaneous velocity of the ball 1 second after it is hit? 3 seconds after it is hit? b. The ball reaches its maximum height above the ground when the instantaneous velocity is zero. After how many seconds does the ball reach its maximum height? What is its maximum height?

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