# For the beam shown in Figure P4-79, use a computer program to determine the and then making the shear area equal 5/6 times the cross-sectional area

For the beam shown in Figure P4-79, use a computer program to determine the and then making the shear area equal 5/6 times the cross-sectional area (b times h). deflection at the mid-span using four beam elements, making the shear area zero Then make the beam have decreasing spans of 200 mm, 100 mm, and 30 mm with 51-4.78 Solve Problems 4.7 through 4.13, 4.21 through 4.. suitable computer program. .79 zero shear area and then 5/6 times the cross-sectional area. Compare the answers Based on your program answers, can you conclude whether your program the effects of transverse shear deformation? includes 50,000 N h = 50 mm 200 mm + b = 25 mm 400 mm Figure P4-79 For the beam shown in Figure P4–79, use a longhand solute 11 M H = Context A : Static Structural – Mechanical [ANSYS Academic Teaching Introductory] File Home Model Display Selection Automation Quick Launch 1 Named Selection F Commands Images ET Coordinate System Comment Section Plane Analysis Remote Point Chart Annotation Insert Print Preview Report Preview Key Assignments Tags Manage Views mft O Wizard iz Selection Information Units Worksheet Keyframe Animation Show Errors Unit Converter Tools Solve Is Manage User Defined Full Screen Reset Layout Layout FOX Select Mode ET DOB C XYZ LOD Clipboard (Empty Extend- 9 Select By Convert Cut X Delete My Computer Copy Q Find ✓ Distributed Duplicate E Paste Tree Cores 2 Outline Solve Outline x Name Search Outline v Project ..- Model (A4) Geometry Materials Cross Sections Coordinate Systems Mesh Static Structural (A5) Analysis Settings O-2 Solution (A6) Solution Information +….. HOX Z Details of “Model (A4)” Lighting Ambient 0.1 Diffuse 0.6 Specular 1 Color Filter Options 0.000 0.050 0.100 (m) 0.025 0.075

I am solving [A first course of in the finite element method] P 4-79 with ANSYS and I know this is about Timoshenko Beam theory

K_s * A = shear area

K_s( shear form factor) = 5/6 (rectangular) or 0

but where i input K_S?