# what-are-the-steps-to-the-boyle-s-law-formula-p1-x-v1-p2-x-v2

Boyle’s law developed by Robert Boyle in 1662, states that if we keep the temperature of a gas constant in a sealed container. Its pressure (P) varies inversely with its volume (V). In other words at any given temperature. If we pressurize a gas its volume will be reduced proportionately to the pressure change. If we increase the volume of a gas its pressure will increase.

I am not sure what you mean by the steps, but I can help you identify a problem, and tell you how to solve it.

Boyle’s Law is that Pressure, P is inversely related to volume, V at constant temperature and number of moles. The mathematical relationship is ##P = k*1/V## which rearranges to

##P*V=k##,

where ##k## is a constant.

Since ##PV=k##, you get ##P_1V_1=P_2V_2##.

You can tell a problem will be a Boyle’s law problem, if there is a change in pressure or volume and it asks you about the other.

For example, you could be asked the following:If a gas at , has its container expand to three times its volume, what is the new pressure.

Solution##P_1 = 760 mmHg####V_1 = V_1##

##P_2 = ?####V_2 = 3V_1## because the new volume is 3 times bigger.

##P_1V_1 = P_2V_2## Boyle’s Law

##P_2 = (P_1V_1)/V_2## Divide both sides by ##V_2##

##P_2 = ((760 mmHg)V_1)/(3V_1)## Substitute givens.

##P_2 = (760mmHg)/3 = 253.3 mmHg##

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