what-is-log-100-log-10

/in /by

##3##

As we know

##log A+log B = log(A * B)##

This means that you can write

##log(100) + log(10) = log(100 * 10)##

##=log(1000)##

##=log(10^3)##

Since

##log(x^n) = n* log(x)##

you can say that

##log(10^3) = 3 * log(10) = 3 * 1 = 3##

-15-

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