what-is-the-equation-of-circle-with-center-at-0-0-and-radius-of-7

##x^2+y^2=49##

The standard form of a circle with a center at ##(h,k)## and a radius ##r## is

##(x-h)^2+(y-k)^2=r^2##

Since the center is ##(0,0)## and the radius is ##7##, we know that

##{(h=0),(k=0),(r=7):}##

Thus, the equation of the circle is

##(x-0)^2+(y-0)^2=7^2##

This simplifies to be

##x^2+y^2=49##

graph{(x^2+y^2-49)=0 [-16.02, 16.03, -8.01, 8.01]}

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